write my assignment 11078

A metal bar with length L, mass m, and resistance R is placed on a frictionless metal rails that are inclined at an angle phi above the horizontal.  The rails have negligible resistance.  A uniform magnetic field B is directed downward on the figure (see attachment).  The bar is released from rest and slides down the rails.I already answered all of the following except for part e.a) Is the direction of the current induced in the bar from a to b, or from b to a?answer: a to bb) What is the terminal speed of the bar?answer: terminal speed = (mg*sin(phi)*R)/(B*L*cos(phi))^2c) What is the induced current in the bar when the terminal speed has been reached?answer: induced current = (m*g/B*L)*tan(phi)d) after the terminal speed has been reached, at what rate is electrical energy being converted to thermal energy?answer: P = I^2*R = ((m*g/B*L)*tan(phi))^2 * Re) After the terminal speed has been reached, at what rate is work being done on the bar by gravity?This one I have no clue how to answerI thought it would be:  W = F*v = mg*((mg*R*sin(phi))/(B*L*cos(phi))^2but this is not the right answer.

A metal bar with length L, mass m, and resistance R is placed on a frictionless metal rails that are inclined at an angle phi above the horizontal.  The rails have negligible resistance.  A uniform magnetic field B is directed downward on the figure (see attachment).  The bar is released from rest and slides down the rails.I already answered all of the following except for part e.a) Is the direction of the current induced in the bar from a to b, or from b to a?answer: a to bb) What is the terminal speed of the bar?answer: terminal speed = (mg*sin(phi)*R)/(B*L*cos(phi))^2c) What is the induced current in the bar when the terminal speed has been reached?answer: induced current = (m*g/B*L)*tan(phi)d) after the terminal speed has been reached, at what rate is electrical energy being converted to thermal energy?answer: P = I^2*R = ((m*g/B*L)*tan(phi))^2 * Re) After the terminal speed has been reached, at what rate is work being done on the bar by gravity?This one I have no clue how to answerI thought it would be:  W = F*v = mg*((mg*R*sin(phi))/(B*L*cos(phi))^2but this is not the right answer.

 
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