Answered>Order 4188

In need of your help. Thank you so much in advance for your help!

The sample space given here shows all possible sequences for a family with 4 children. where B EGGS 5353 5553 GEES BEBE ‘3 stands for boy and G stands for girl. It all 15 5535 GBGB BIS EBoutcomes are equally likely, ?nd the probability that there are: 5365 GBBG EBGBa. exactly [1 boys. by BEECH}! 1 girl, EGGS BGGB BEBEo. exactly 2 girls. BGBG d. exactly 3 girls. e. exactly 4 girls. BEES e. The probability of exactly ? boys is E. {Type an integer or a simpli?ed fraction}b. The probability of exactly 1 girl is El. {Type an integer or a simpli?ed traction}o. The probability of exactly 2 girls is D. {Type an integer or a simpli?ed fraction.)d. The probability of exactly 3 girls is E {Type an integer or a simpli?ed traction.) e. The probability of exactly 4 girls is El {Type an integer or a simpli?ed traction.)