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write my assignment 21025

Compose a 1750 words essay on A Comparison Among the Writings of Taylor, Palmer and Emerson. Needs to be plagiarism free!

It is the classic quandary: if an all-powerful God loved us, why does He allow a man to be harmed by evil?

Taylor’s response reconciles God as all-good, man as a moral being, and evil as the result of human choice. Moral depravity is his sinful character, his “state of mind and heart” that pertains to “guilt” and “wrath”. God created man to be good, but at the same time allows man the choice of whether to be obedient to His divine will or to pursue his own selfish interests. Man is saved if he chooses to follow God’s will rather than his own.

Sin, therefore, is seen as an integral part of salvation. By giving in to his moral depravity, man creates the evil, not God. However, because he has a choice, man can rise from this moral depravity and choose God, thereby meriting salvation. God did not create the evil, but by allowing man the freedom to choose evil he also afforded man the chance to choose well. This debunks the notion that God could have prevented all sin or at least the present degree of sin.

In Taylor’s works, he speaks of God as a personal Father, with a mind and will whose intentions man tries to understand. God provides the opportunity for man to exercise his moral nature, that is, to choose the virtuous over the evil. The interaction between God and man is one of dynamic interaction, with God offering the choice and man taking the volition to make the choice.

Palmer was more of a mystical writer. She espoused the experience of holiness as the road to sanctification. Holiness is seen as a mystical union with God. It is only when one abandons his own efforts and surrenders all to God that he gets to experience the faith necessary for him to live a sinless life.

Sanctification is obtained when one is united with Christ, bathed in the blood of Christ, because it is only through Him that man can reach God.

 

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write my assignment 12667

CJ 790 1-1 Discussion: Getting Started

watch the following webinar: The Writing’s on the Wall: Communicating Your Qualifications Using a Portfolio. This will provide you with an understanding of ePortfolios and their purpose. Then, discuss how you have developed your professional ePortfolio up to this point. What do you hope your ePortfolio will look like at the completion of this program? Discuss how you plan to use your ePortfolio in the future.In your responses to your peers, comment on their experiences in the criminal justice field. Are your goals for your career and ePortfolio similar or different? Include any advice or suggestions you have to offer to your peers in your responses.

Refer to the Capstone Discussion Rubric for directions on completing your module discussion.

I’m working as a Correction Officer now, but looking to swich over to a nother field in CJ.

 

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write my assignment 27468

Fast Fashion and the Ethics of Low Cost Labor

Please help with attached case study three questions st the bottoms of attachment

  • Attachment 1
  • Attachment 2
  • Attachment 3

"I Xfinity Mobile LTE10: 12 AM8 17% [A online . warner . eduFast – Fashion and the Ethics of Low – Cost LaborWho wants to wait six months for runway looks to hit thestores ? In today’s fast- fashion world , six months is an eternity .Nearly extinct is the tradition of three luxurious fashion seasonsper year ( fall , spring , resort ) . Those seasons have been replacedby rock – bottom prices on 30 to 50 trend – driven cycles – per year .Consumers in the United States and Europe have embraced the*entire fast – fashion approach – inexpensive apparel and highturnover of designs . In fact , their shopping behaviors haveallowed companies like HEM and Zara to grow intointernational retailing behemoths .The speed of fast- fashion goes beyond the production cycle .Europe’s fast – fashion chains have grown faster than the retailfashion industry as a whole , partly because the combination oflow cost , fresh designs , and quick turnover is extremely*successful in fueling consumer demand . Fast- fashion companiesalso boast higher margins that those reported by their traditionalcounterparts – an average 16 percent compared to an average of7 percent . Undeniably , the application of planned obsolescence*to fashion has been financially successful .The fast – fashion approach is not without controversy , however ,particularly when it comes to outsourcing production .Companies like Benetton , Walmart , and Disney place hugeorders with off shore vendors who often cannot deliver the entire*order without enlisting the help of additional subcontractors .Unauthorized subcontracting is the end result , and brands don’talways know who is producing their products or where . PhilRobertson , deputy director of Human Rights Watch’s Asiadivision , affirms this , saying , " I’ve talked to Thai workers whoare three or four levels down from the original orders . If thebrands don’t know , they should know . A lot of them are turning*a blind eye to outsourcing . "One country that has grown from outsourcing in the garmentindustry is Bangladesh . With labor rates averaging $40 permonth , Bangladeshi garment workers are the cheapest around .( Compare that to approximately $120 per month on average forgarment workers in China . ) Those low labor costs have causedexplosive growth in the size and scope of the country’s garmentindustry . In 2005 , the country exported $6 . 9 billion worth ofclothing . By 2011 , that figure had risen to $19.9 billion , making*the Bangladesh the world’s third largest exporter of clothing*behind China and Italy .Makeshift garment factories have popped up all over

 

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write my assignment 29116

Hi so Im creating a fraction calculator that also finds the gcd. My problem is that everytime I do the addition operator it comes out different from what I expect.

My code is below:

#include <iostream>

using namespace std;

double gcd (int, int);

int main (){

   char op, slash, repeat;

   int num1, den1, num2, den2, resNum1, resNum2, big, small, ans;

do{   

   cout << “Enter the first fraction: “;

   cin >> num1 >> slash >> den1;

      while (den1 == 0){

         cout << “Denominators cannot be equal to zero. Please reenter entire fraction with valid input: “;

         cin >> num1 >> slash >> den1;

      };

   cout << “Enter operation: “;

   cin >> op;

   cout << “Enter the second fraction: “;

   cin>> num2 >> slash >> den2;

      while (den2 == 0){

         cout << “Denominators cannot be equal to zero. Please reenter entire fraction with valid input: “;

         cin>> num2 >> slash >> den2;

      };

   switch (op){   

      case ‘+’:

         resNum1 = (num1*den2 + num2*den1);

         resNum2 = (den1*den2);

            if (resNum1 > resNum2){

            big = num1;

            small = num2;

            }

            else {

            small = resNum1;

            big = resNum2;

            }

         ans = gcd (small, big);

         cout << resNum1/ans << “/” << resNum2/ans;            

         break;

      case ‘-‘:

         resNum1 = (num1*den2 – num2*den1);

         resNum2 = (den1*den2);

            if (resNum1 > resNum2){

            big = num1;

            small = num2;

            }

            else {

            small = resNum1;

            big = resNum2;

            }

         ans = gcd (small, big);

         cout << resNum1/ans << “/” << resNum2/ans;            

         break;

      case ‘/’:

         resNum1 = (num1*den2);

         resNum2 = (num2*den1);

            if (resNum1 > resNum2){

            big = num1;

            small = num2;

            }

            else {

            small = resNum1;

            big = resNum2;

            }

         ans = gcd (small, big);

         cout << resNum1/ans << “/” << resNum2/ans;            

         break;

      case ‘*’:

         resNum1 = (num1*num2);

         resNum2 = (den1*den2);

            if (resNum1 > resNum2){

            big = num1;

            small = num2;

            }

            else {

            small = resNum1;

            big = resNum2;

            }

         ans = gcd (small, big);

         cout << resNum1/ans << “/” << resNum2/ans;   

         break;

      default: break;

   }   

   do{

      cout << “nContinue? (y/n): “;

      cin >> repeat;

   } while (repeat != ‘y’ && repeat != ‘Y’ && repeat != ‘n’ && repeat != ‘N’);

} while (repeat == ‘y’ || repeat == ‘Y’);

   return 0;

}

double gcd (int small, int big){

   int rem;

   rem = big%small;

   while (rem != 0){

      small = rem;

      rem = big%rem;

   }

   return (small);

}

 

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