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write my assignment 3881

Consider a closed economy to which the Keynesian-cross analysis applies as follows

C=300+0.5(Y-T)

T = 400

I = 400

G = 400

C = Consumption

T = Taxes

I = Planned Investment

G = Government Spending

Part 1: If y = 1500 what is planned spending?

Part 2: What is the value of inventory accumulation (use – symbol if negative)?

Part 3: What is Equilibrium Y?

Part 4: what is equilibrium consumption?

Part 5: What is private saving?

Part 6: What is public saving?

Part 7: What is national saving?

Part 8: if G is reduced to 200, how much does equilibrium income decrease (Use – for decrease)

Part 9: What is the multiplier for government spending?

 

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write my assignment 13404

Compose a 250 words essay on Discuss potential reasons for a groups failure to meet their goals and objectives. Needs to be plagiarism free!

Lack of proper timing may be a possible cause of failure by group members to undertake strategies aimed at accomplishing set goals and objectives of a group project.

Goals and objectives need close supervision to ensure the set strategies to accomplish them are in the right track. Proper reporting of progress is vital to realizing the set goals and objectives of the group. Failure to undertake supervision of the progress, coupled with proper reporting may be a possible cause of unattained goals and objectives in a group project (Yarbrough, 2008). Besides supervision, the progress of the goals should be subject to evaluation for appropriateness and relevance. This is a core step to realizing goals and objectives of a group project. Planning plays a fundamental role in realizing set goals and objectives. A plan serves as a blueprint that guides the strategies of achieving set goals and objectives. A group, therefore, needs a detailed and well-defined plan to guide it through the course of the process. Failure to set an appropriate plan, therefore, can be a possible cause of failure to achieve a group’s set goals and

 

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write my assignment 27976

Need help writing 2 classes for a comp sci assignment.

The first class – private static void performCompression(String inputFileName, String ccName, String outputFilename);

The second class is the decompression class, which does the opposite of the compression class.

This class essentially takes as input a file containing a String of characters, say “the fox jumped over the [email protected]!?”

The second input: ccName, is a file containing a bunch of compression codes in the format: “t10100”

“h0010”

……..

“@0100100”

etc.

Essentially what needs to be done is compression and decompression. For compression, take each letter from the inputFileName, find it in the ccName file, then match the code and add it to the outputFileName. For decompression, do the opposite.

So an example output for [email protected] using the codes above would be 1010000100100100 in the output file.

The methods provided are:

an array constructor and array getter and setter methods: The object of the array is CodeSet. So we have the constructor as public CodeSet(char a, String code){

We have the getter and setter methods: getCode(), getCharacter(), setCode(), setCharacter(), and a method equals(CodePair, anotherPair) which checks if two CodePairs are equal.

In addition to this we have the file methods of:

public CompressedFile(String fileName, String fileMode){

//constructor. checks if the specifed name corresponds to an existing file and if so

it opens the file

public void writeBit(char bit){

//Writes a character to the output file, where bit is the bit to write to the output file (ex: 10100 for “t”)

We also have public char readBit(){

//Reads the next bit from the input file. If all the bits have been read this method returns EOF (end of file). Bit returned is first converted to a char, so this method returns a bit as either ‘0’ or ‘1’.

public String readLine()

//Reads characters from the current position of the input file until the end of line

    is reached. The String read is returned. 

    returns String of characters from current position in input file until the end of line.

   returns null if there are no more characters to read from the file.

we also have public char readChar()

Reads the next character from the input file. If all the characters have been read this method returns EOF (end of file) = 0

It returns Next character from the input file .

these methods are already created^^ essentially I just need help with reading the file into the array, and then comparing that array to the input text file and writing the resulting bits to the output file.

Also, similarly, the decompression algorithm for this, which uses the methods readBit() and writeBit() I provided as well as the others.

Thanks!

 

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write my assignment 4834

A sample of oxygen (O2) was collected by water displacement at 23°C when the ambient pressure was 754 torr. The volume of the gas over water was 613 mL. If the water vapour could be removed from the gas sample, what volume (in mL) would the dry O2 gas occupy under the same conditions?

The vapour pressure of water at 23°C is 21.0 torr.

Which of the following relationships is not true for an ideal gas?

Select one:

A. PV = constant when temperature and moles of gas are held constant

B. V/T = constant when pressure and moles of gas are held constant

C. nT = constant when pressure and volume are held constant

D. P/n = constant when volume and temperature are held constant

E. All the statements in this question are true

 

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